Thread: [FCFS] Friday Paypal Giveaway #6

Good morning dear members ,
this will be a little different from the previous giveaways , the first one who find the answer will be the winner:

Don't give the answer just like that (it won't count), you need to write the steps using Paint or a picture.
If you're an AngeClub member you will win 4$ PayPal.
If you're a Regular member you will get 2$ PayPal
Regards,
Angemon

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Originally Posted by shadypro

meeeeeeeeeeeeeeeeee

you what ? (your bot won't help you this time)

Originally Posted by shadypro

meeeeeeeeeeeeeeeeee

bot dont work here
Btw never seen this sh*t in my life so good luck all ..

Just use log rules: ln(2n) = ln(2) + ln(n). Therefore, you have
lim (n→∞) ln(n) / [ln(2) + ln(n)]
= lim (n→∞) 1 / [ln(2) / ln(n) + 1]
= 1 / (0+1)
= 1.
?
PIC Screenshot by Lightshot or Screenshot by Lightshot

Originally Posted by Ryuzaki

Just use log rules: ln(2n) = ln(2) + ln(n). Therefore, you have
lim (n→∞) ln(n) / [ln(2) + ln(n)]
= lim (n→∞) 1 / [ln(2) / ln(n) + 1]
= 1 / (0+1)
= 1.
?

you need to write the steps using Paint or a picture.

Originally Posted by Angemon

you need to write the steps using Paint or a picture.

post edited

Originally Posted by Ryuzaki

post edited

I can't understand what you wrote there that's why I asked people to use paint so I can understand, I didn't ask for screenshot for your texts.
you're writing ln(n) / [ln(2) + ln(n)] and in my question it's [ln(2) + ln(n)] / ln(n) , totally different.

Originally Posted by Angemon

I can't understand what you wrote there that's why I asked people to use paint so I can understand, I didn't ask for screenshot for your texts.
you're writing ln(n) / [ln(2) + ln(n)] and in my question it's [ln(2) + ln(n)] / ln(n) , totally different.

Okay just tried
Good luck everybody !